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Potassium Bicarbonate
Potassium Bicarbonate
If 0.532g of potassium bicarbonate is heated in air, what is the mass of potassium carbonate obtained?
First, write a balanced equation for the reaction:
2 KHCO3 → K2CO3 + CO2 + H2O
Next, use dimensional analysis and equation coefficients to convert 0.532 of potassium bicarbonate to moles of potassium bicarbonate, then to moles of potassium carbonate, and finally to grams of potassium carbonate.
[(0.532 g KHCO3)/1][(1 mol KHCO3)/(100.114 g KHCO3)][(1 mol K2CO3)/(2 mol KHCO3)][(139.202 g K2CO3)/(1 mol K2CO3)] = 0.370 g of K2CO3
Answer: 0.370 g of potassium carbonate is obtained when 0.532 g of potassium bicarbonate is heated in air.
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